x^2-0.3x=0.1

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Solution for x^2-0.3x=0.1 equation:



x^2-0.3x=0.1
We move all terms to the left:
x^2-0.3x-(0.1)=0
We add all the numbers together, and all the variables
x^2-0.3x-0.1=0
a = 1; b = -0.3; c = -0.1;
Δ = b2-4ac
Δ = -0.32-4·1·(-0.1)
Δ = 0.49
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-0.3)-\sqrt{0.49}}{2*1}=\frac{0.3-\sqrt{0.49}}{2} $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-0.3)+\sqrt{0.49}}{2*1}=\frac{0.3+\sqrt{0.49}}{2} $

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